Question

A block of wood is floating in the water. The portion of the block inside water measures 50 cm x 50 cm x 50 cm. What is the magnitude of the buoyant force acting on the block? (Take the density of water as 1 g cm-3)

Answer 1

Step 1: Given Data

volume of the box,$V$$=50cm\times 50cm\times 50cm$

$$\begin{gathered} =0.5m\times 0.5m\times 0.5m \\ =0.125m^3 \end{gathered}$$

density of water,$p$$=1000Kg/m^3$

acceleration due to gravity,$g=10m/s^2$

Buoyant force,$F_B$

Step 2: Relation between the buoyant force and density

$F_B=pVg$

Step 3: Finding the value of the buoyant force

$$\begin{gathered} F_B=pVg \\ =1000\times 0.125\times 10 \\ =1250N \end{gathered}$$

Hence, the buoyant force is $1250N$