1
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Question

# A block of wood of mass 3 M is suspended by a string of length 10/3 m. A bullet of mass M hits is with a certain velocity and gets embedded it. The block and the bullet swing to one side till the string makes 1200 with the initial position. Find the velocity of the bullet (g=10ms−2)

A
403ms1
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B
20ms1
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C
30ms1
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D
40ms1
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Solution

## The correct option is C 40ms−1Using energy conservation,Potential energy change = Kinetic Energy1/2(4m)v2=(4m)g×(10/3+10/3sin30∘)=20mgv=10Using momentum conservation,mv=(m+3m)(10)⇒v=40m/s.

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