A block of wood of mass $5 k g$ is suspended by a thread. A gun is fired in the horizontal direction and the bullet strikes the block and is embedded in it. As a result, the block is raised to $15 c m$ . If the mass of the bullet be $20 g$ , find the initial velocity of the bullet. $(g = 9.8 {m s}^{- 2})$

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Solution

conservation of energy

$\frac{1}{2} m v^{2} = m g h$

$V^{2} = 2 g h$

V = 1.715 m / s

Applying
conservation of momentum

$μ$ = ( m + M ) V

solving
$U = \frac{8.607}{0.02}$

= 430 m / s

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A block of wood of mass 5 kg is suspended by a thread. A gun is fired in the horizontal direction and the bullet strikes the block and is embedded in it. As a result, the block is raised to 15 cm. If the mass of the bullet be 20 g, find the initial velocity of the bullet. (g=9.8ms−2)

conservation of energy 12mv2=mghV2=2gh V = 1.715 m / sApplying conservation of momentum μ = ( m + M ) V solving U=8.6070.02 = 430 m / s

conservation of energy

$\frac{1}{2} m v^{2} = m g h$

$V^{2} = 2 g h$

V = 1.715 m / s

Applying
conservation of momentum

$μ$ = ( m + M ) V

solving
$U = \frac{8.607}{0.02}$

= 430 m / s