A block weighing 22N is held against a vertical wall by a horizontal force 60N. The coefficient of static friction between the wall and the block is 0.55 and the coefficient of kinetic friction between them is 0.38. A second force acting parallel to the wall is applied to the block.Calculate the minimum force required to set the block in motion and calculate the force required to keep the block in uniform motion.

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Solution

Dear Student,

$W = 22 N F = 60 N m a x i m u m f r i c t i o n a l f o r c e a t s t a t i c = 60 * 0.55 = 33 N t h e f o r c e r e q u i r e d t o = s e t t h e b l o c k i n m o t i o n = 33 - 22 = 11 N f o r c e r e q u i r e d t o s e t i n u n i f o r m m o t i o n = 60 * 0.38 - 22 = 22.8 - 22 = 0.8 N R e g a r d s$

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Dear Student, W=22 N F=60Nmaximum frictional force at static=60*0.55=33 N the force required to =set the block in motion =33-22=11 N force required to set in uniform motion =60*0.38-22=22.8-22=0.8N Regards