Question

A BMW car travelling at $22.4$ m/s skids to a stop in $2.55$s. Determine the skidding distance of the car.(assume uniform acceleration)

Answer 1

$U=22.4\frac{m}{s}$

$v=0$

$t=2.55s$

$v=u+at$

$0=22.4+a\times 2.55$

$-22.4=2.55a$

$\frac{-22.4}{2.55}=a$

$8.784=a$

$a=8.784\frac{m}{s²}$

$v^2+u^2=2as$

$0={\left(22.4\right)}^2+2\times s\times (-8.784)$ $-501.76=-17.568$

$s=28.56m$ before car stops it travel by skidding.