Question

A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration a directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration a vertically. The tension in the string is equal to

• A. $m\sqrt{g^2+a^2}$
• B. $m\sqrt{g^2+a^2}-ma$
• C. $m\sqrt{g^2+a^2}+ma$
• D. $m(g+a)$

Answer 1

The correct option is C

$m\sqrt{g^2+a^2}+ma$

$T-\sqrt{(mg{)}^2+(ma{)}^2}=ma$

$T=m\sqrt{g^2+a^2}+ma$