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Question

A body A is thrown vertically upward with the initial velocity v1. Another body B is dropped from a height h. Find how the distance x between the bodies depends on the time t if the bodies begin to move simultaneously.

A
x=hv1t
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B
x=(hv1)t
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C
x=hv1t
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D
x=htv1
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Solution

The correct option is A x=hv1t
Let the distance covered by body A be h1
h1=v1t12gt2
and, let the distance travelled by the body B be h2
h2=0+12gt2
Given, the distance between the bodies is x=h(h1+h2)
h1+h2=v1t
x=hv1t
Hence, the distance x between the bodies depends on the time t if the bodies begin to move simultaneously as x=hv1t

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