wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body A of mass 150 kg, travelling at 20 m/s collides with a body B of mass 100 kg travelling at 10 m/s in the same direction. After collision the velocity of A becomes 15 m/s. What is the magnitude of velocity of B after the collision?

A
22.5 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
17.5 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
5 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12.5 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 17.5 m/s
Given : mA=150 kg uA=20 m/s mB=100 kg uB=10 m/s vA=15 m/s

Let the speed of B after the collision be vB.

Using conservation of linear momentum before and after the collision :
Pi=Pf

mAuA+mBuB=mAvA+mBvA

OR 150×20+100×10=150×15+100vB

vB=17.5 m/s

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservation of Momentum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon