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Standard XIII

Physics

Multiplication with Vectors

A body, acted...

Question

A body, acted upon by a force of $50 N$ is displaced through a distance $10$ meter in a direction making an angle of $60^{\circ}$ with the force. The work done by the force be

200 J

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100 J

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300 J

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250 J

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Solution

The correct option is D $250 J$
$W = \to F . \to S = F S cos θ$
$= 50 \times 10 \times cos 60^{\circ} = 50 \times 10 \times \frac{1}{2}$
$= 250 J$

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