A body acted upon by a force of 50 N is displaced through a distance 10 m in a direction making an angle of 60- with the force- The work done by the force isTake W-F- S- where W is work done- F is force and S is the displacement

A body, acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of $60^{\circ}$ with the force. The work done by the force be

Q. A force of

10 N

displaces an object by

10 m

. If work done is

50 J

, then direction of force makes an angle with direction of displacement

A 20 N force displaces a body by 10 m. The angle between force and direction of displacement is 60°. Calculate the work done.

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A body acted upon by a force of 50 N is displaced through a distance 10 m in a direction making an angle of 60∘ with the force. The work done by the force is (Take W=→F.→S, where W is work done, →F is force and →S is the displacement)

The correct option is D 250 JWork done by a force →F in moving a body through diplacement →S W=→F.→S=FScosθ=50×10×cos60∘=50×10×12=250 J.

A body acted upon by a force of $50 N$ is displaced through a distance $10 m$ in a direction making an angle of $60^{\circ}$ with the force. The work done by the force is
(Take $W = \to F . \to S$ , where $W$ is work done, $\to F$ is force and $\to S$ is the displacement)

The correct option is D $250 J$
Work done by a force $\to F$ in moving a body through diplacement $\to S$
$W = \to F . \to S = F S cos θ = 50 \times 10 \times cos 60^{\circ} = 50 \times 10 \times \frac{1}{2} = 250 J .$