Question

A body at rest is falling freely under gravity. The distance travelled by the body in the first 3 s is equal to the distance traveled by the same body in the same body in the nth second. What is the value of n?

• A. 3
• B. 4
• C. 5
• D. 6

Answer 1

The correct option is C 5

Distance covered in nth second $=u+\frac{1}{2}a(2n-1)$

Distance covered in 't' second in free fall $=\frac{1}{2}g{t}^2$

According to question, we have

$u+\frac{1}{2}g(2n-1)$ $=\frac{1}{2}g{t}^2$

$\Rightarrow 2n-1=9$

$\Rightarrow n=5$

Therefore, C is correct option.