A body cover a distance of $^{'} x^{'}$ metre along a semicircular path. Calculate the ratio of it's distance to displacement.

Open in App

Solution

Distance $= \frac{2 π r}{2}$
Displacement $= 2 r$
$\frac{D i s t a n c e}{D i s p l a c e m e n t} = \frac{2 π r}{2 \cdot 2 r} = \frac{π}{2} = \frac{22}{14}$

Suggest Corrections

Similar questions

Q. A body covered a distance of Lm along a curved path of a quarter circle.The ratio of distance to displacement.

Q. A body moves along a curved path of a quarter circle.Calculate the ratio of distance to displacement :

A body covered a distance of X meters along a semi-circular path. calculate the magnitude of displacement of the body and the ratio of distance to displacement.

Q. A body moves along curved path of a quarter circle. The ratio of magntude of displacement to distance is

Q. A particle moves from A to B along the semicircular curve as shown in the figure. The ratio of distance covered by particle to its displacement is

Join BYJU'S Learning Program

A body cover a distance of ′x′ metre along a semicircular path. Calculate the ratio of it's distance to displacement.

Distance =2πr2Displacement =2rDistanceDisplacement=2πr2⋅2r=π2=2214

A body cover a distance of $^{'} x^{'}$ metre along a semicircular path. Calculate the ratio of it's distance to displacement.

Distance $= \frac{2 π r}{2}$
Displacement $= 2 r$
$\frac{D i s t a n c e}{D i s p l a c e m e n t} = \frac{2 π r}{2 \cdot 2 r} = \frac{π}{2} = \frac{22}{14}$