The correct option is
C 10cm/secStep 1: Applying equation of motion
Since acceleration is constant, therefore we can apply equation of motion.
In first case: When body covers 200cm in 2s:
s1=ut1+12at21
⇒ 200=u(2)+12a(2)2
⇒ a+u=100 ....(1)
In second case: Total displacement, s2=200 cm+220 cm=420 cm
Total time: t2=2 s+4 s=6 s
s2=ut2+12at22
⇒420=u(6)+12a(6)2
⇒ u+3a=70 ....(2)
Step 2: Initial velocity and acceleration
Subtracting eqn(1) from (2)
2a=−30⇒a=−15 cm/s2
Putting the value of a in equation (1) we get, u=115 cm/s
Step 3: Velocity at the end of 7th second
Velcity at the end of 7th second:
v=u+at =115−15×7=10 cm/s
Hence, Option C is correct.