A body drinks $500$ ml of $9$ % glucose solution. The number of glucose molecules he has consumed is :
$[M o l . w t . o f g l u c o s e = 180]$

0.5 \times 10^{23}

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1.0 \times 10^{23}

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1.5 \times 10^{23}

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2.0 \times 10^{23}

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Solution

The correct option is B $1.5 \times 10^{23}$
According to given conditions,
$G l u c o s e i n 500 m L s o l u t i o n = \frac{9 \times 500}{100}$
$= 45 g$
$= \frac{45}{180} = 0.25 m o l$
$= 0.25 \times 6.02 \times 10^{23} m o l e c u l e s$
$= 1.5 \times 10^{23}$

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A body drinks 500 ml of 9% glucose solution. The number of glucose molecules he has consumed is : [Mol.wt.ofglucose=180]

The correct option is B 1.5×1023According to given conditions,Glucosein500mLsolution=9×500100 =45g =45180=0.25mol =0.25×6.02×1023molecules =1.5×1023

A body drinks $500$ ml of $9$ % glucose solution. The number of glucose molecules he has consumed is :
$[M o l . w t . o f g l u c o s e = 180]$

The correct option is B $1.5 \times 10^{23}$
According to given conditions,
$G l u c o s e i n 500 m L s o l u t i o n = \frac{9 \times 500}{100}$
$= 45 g$
$= \frac{45}{180} = 0.25 m o l$
$= 0.25 \times 6.02 \times 10^{23} m o l e c u l e s$
$= 1.5 \times 10^{23}$