Question

A body executes SHM under the influence of one force with time period of $3s$ and the same body executes a SHM with a time period of $4s$ under the influence of a second force. If both the forces are acting simultaneously then , the time period of the same body will be

• A. $2\sqrt{3}s$
• B. $7s$
• C. $5s$
• D. $2.5s$

Answer 1

The correct option is D $2.5s$

When both the forces acts together, the time taken will be:
So, $T=\frac{T_1{T}_2}{\sqrt{T_1^2+T_2^2}}=\frac{3\times 4}{5}=2.5s$