A body falls freely from rest. It covers as much distance in the last second of its motion as covered in the first three seconds. The body has fallen for a time;

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Solution

The correct option is B
5s

We have

$\frac{1}{2} g (3)^{2} = \frac{g}{2} (2 n - 1) \Rightarrow n = 5 s$

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A body falls freely from rest. It covers as much distance in the last second of its motion as covered in the first three seconds. The body has fallen for a time;

The correct option is B 5s We have 12g(3)2=g2(2n−1)⇒n=5s

The correct option is B
5s

We have

$\frac{1}{2} g (3)^{2} = \frac{g}{2} (2 n - 1) \Rightarrow n = 5 s$