# Dropping Objects

## Trending Questions

**Q.**

A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of the tower is

(g=10 m/s2)

- 90 m
- 45 m
- 55 m
- 60 m

**Q.**A body dropped from the top of a tower falls through 40 m during the last two seconds of its fall. The height of tower is (g=10 m/s2)

- 60 m
- 45 m
- 80 m
- 50 m

**Q.**

A body falls freely from rest. It covers as much distance in the last second of its motion as covered in the first three seconds. The body has fallen for a time;

3s

5s

7s

9s

**Q.**

A motor car moving with a uniform speed of 20 ms−1 comes to rest on the application of brakes after travelling a distance of 10 m. Its acceleration is

20m/sec2

−20m/sec2

−40m/sec2

+2m/sec2

**Q.**A ball takes t second to fall from a height h1 and 2t seconds to fall from a height h2. Then h1h2 is:

- 1.5
- 1
- 0.50
- 0.25

**Q.**An object is released from some height. Exactly after one second, another object is released from the same height. The distance between the two objects exactly after 2 seconds of the release of second object will be

- 4.9 m
- 9.8 m
- 19.6 m
- 24.5 m

**Q.**A ball is thrown vertically upwards with a speed of 9.8 m/s from the top of tower. If it returns to ground in 3 seconds, find the height of tower. (Take g=9.8 m/s2)

- 58.6 m
- 14.7 m
- 18.9 m
- 24.3 m

**Q.**A stone is dropped into a well in which the level of water is h below the top of well. If V is the velocity of sound, the time T after which the splash is heard is given by

- T=2hV
- T=√2hg+hV
- T=√2hg−hV
- T=√h2g+2hV

**Q.**A stone falls freely from rest and the total distance covered by it in the last second of its motion equals the distance covered by it in the first three second of its motion. The stone remains in the air for

- 6 s
- 5 s
- 7 s
- 4 s

**Q.**From a tap 10 m high, water drops fall at regular intervals. When the first drop reaches the ground, the 5th drop is about to leave the tap. Find the separation between 2nd and 3rd drops.

- 358 m
- 318 m
- 278 m
- 258 m

**Q.**

A body is released from a great height and falls freely towards the earth. Another body is released from the same height exactly one second later. The separation between the two bodies, two seconds after the release of the second body is

4.9 m

9.8 m

19.6 m

24.5 m

**Q.**

A stone dropped from the top of the tower touches the ground in 4 sec. The height of the tower is about

80 m

40 m

20 m

160 m

**Q.**A ball is thrown vertically upwards with a speed of 9.8 m/s from the top of tower. If it returns to ground in 3 seconds, find the height of tower. (Take g=9.8 m/s2)

- 58.6 m
- 14.7 m
- 18.9 m
- 24.3 m

**Q.**A ball is released from the top of a tower of height h. It takes time T to reach the ground. What is the position of the ball from ground after time T3?

- h9 m
- 7h9 m
- 8h9 m
- 17h18 m

**Q.**Two balls of different masses ma and mb are dropped from two different heights a and b. The ratio of time taken by the two to drop through these distances is

- a:b
- b:a
- √a:√b
- a2:b2

**Q.**A balloon is moving vertically with a velocity of 4 m/s. When it is at a height of h, a ball is gently released from it. If it reaches the ground in 4 s, the height of the balloon when the body is released is

- 80 m
- 96 m
- 64 m
- 78 m

**Q.**A stone is dropped from the 25th storey of a multi-storeyed building and reaches the ground in 5 s. In the first second, it passes through how many storeys of the building? (g=10 m/s2).

- 1
- 2
- 3
- None of these

**Q.**A ball is released from the top of a tower of height h meters. It takes T seconds to reach the ground. What is the position of the ball in T3 seconds

- h9 metres from the ground
- 7h9 metres from the ground
- 8h9 metres from the ground
- 17h18 metres from the ground

**Q.**

A ball is dropped from a height of 5 m. Find the velocity with which it hits the ground.

10 m/s

√−100m/s

5 m/s

- 10 m/s

**Q.**A ball is thrown vertically upwards with a speed of 9.8 m/s from the top of tower. If it returns to ground in 3 seconds, find the height of tower. (Take g=9.8 m/s2)

- 58.6 m
- 14.7 m
- 18.9 m
- 24.3 m

**Q.**An object is released from some height. Exactly after one second, another object is released from the same height. The distance between the two objects exactly after 2 seconds of the release of second object will be

- 4.9 m
- 9.8 m
- 19.6 m
- 24.5 m

**Q.**From the top of a tower of height 200 m, a ball A is projected up with 10 ms−1 and 2 s later another ball B is projected vertically down with the same speed. Then (Neglect air friction)

- Both A and B will reach the ground simultaneously
- Ball A will hit the ground, 2 s after B hits the ground
- Both the balls will hit the ground with the same velocity
- Both the balls will hit the ground with the different velocity

**Q.**Two bodies A (of mass 1 kg) and B (of mass 3 kg) are dropped from height of 16 m and 25 m, respectively. The ratio of the time taken by them to reach the ground is

- 45
- 54
- 125
- 512

**Q.**

If I drop a ball from a height of 5 m then how long will it take to reach the ground?

1

2

3

5

**Q.**

A motor car moving with a uniform speed of 20 ms−1 comes to rest on the application of brakes after travelling a distance of 10 m. Its acceleration is

20m/sec2

−20m/sec2

−40m/sec2

+2m/sec2

**Q.**A stone is dropped from a bridge and it reaches the ground in 4 seconds. The height of the bridge is

- 78.4 m
- 64.2 m
- 98.6 m
- 116.8 m

**Q.**A body falls from rest under gravity and travels half of its total path in the last second. Find the time of fall. (Take g=10 ms−2)

- 2.8 s
- 3.4 s
- 3.8 s
- 4.2 s

**Q.**

If I dropped a Metal ball of weight 10kg and a feather and If I can Imagine that there is no air resistance, then, . Which do you think will reach the ground first?

The 10kg ball

feather

they will land together

I tried and don't have an answer

**Q.**A stone is dropped from a certain height which can reach the ground in 5 second. If the stone is stopped after 3 second of its fall and then allowed to fall again, then the time taken by the stone to reach the ground for the remaining distance is

- 2 sec
- 3 sec
- 4 sec
- None of these

**Q.**

A body A is thrown vertically upward with the initial velocity v1. Another body B is dropped from a height h. Find how the distance x between the bodies depends on the time t if the body begin to move simultaneously.

- x=(h−v1)t
- x=h−v1t
- x=h−v1t
- x=ht−v1