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Question

A stone is dropped from a bridge and it reaches the ground in 4 seconds. The height of the bridge is

A
78.4 m
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B
64.2 m
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C
98.6 m
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D
116.8 m
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Solution

The correct option is A 78.4 m
From the question, it is clear that u=0
Time to reach the ground is t=4 sec
Applying 2nd law of motion for constant acceleration, we have
s=ut+12at2
h=0+12×9.8×(4)2=78.4 m
Hence, height of the bridge is h=78.4 m

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