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Question

From the top of a tower of height 200 m, a ball A is projected up with 10 ms1 and 2 s later another ball B is projected vertically down with the same speed. Then (Neglect air friction)

A
Both A and B will reach the ground simultaneously
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B
Ball A will hit the ground, 2 s after B hits the ground
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C
Both the balls will hit the ground with the same velocity
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D
Both the balls will hit the ground with the different velocity
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Solution

The correct option is C Both the balls will hit the ground with the same velocity
Ball A will return to the top of tower after
T=2ug=2×1010=2 s
with a speed of 10 ms1 downward.
And at the same moment B is also projected downward with 10 ms1.
So both reach ground simultaneously. Also they will hit the ground with same speed.

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