A stone is dropped from the $25^{t h}$ storey of a multi-storeyed building and reaches the ground in $5 s$ . In the first second, it passes through how many storeys of the building? $(g = 10 m / s^{2})$ .

1

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Solution

The correct option is A $1$
Suppose $h$ be the height of each storey
By using second equation of motion, we know that
$s = u t + \frac{1}{2} a t^{2}$
As the stone is at rest initially
$\Rightarrow u = 0$
Then, $25 h = 0 + \frac{1}{2} \times 10 \times t^{2}$
$= \frac{1}{2} \times 10 \times 5^{2}$
$\Rightarrow h = 5 m$
In first second, let the stone passes through $n$ storeys.
So, $n \times 5 = \frac{1}{2} \times 10 (1)^{2}$
$\Rightarrow n = 1$

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A stone is dropped from the 25th storey of a multi-storeyed building and reaches the ground in 5 s. In the first second, it passes through how many storeys of the building? (g=10 m/s2).

The correct option is A 1Suppose h be the height of each storey By using second equation of motion, we know that s=ut+12at2 As the stone is at rest initially ⇒u=0 Then, 25h=0+12×10×t2 =12×10×52 ⇒h=5 m In first second, let the stone passes through n storeys. So, n×5=12×10(1)2 ⇒n=1

A stone is dropped from the $25^{t h}$ storey of a multi-storeyed building and reaches the ground in $5 s$ . In the first second, it passes through how many storeys of the building? $(g = 10 m / s^{2})$ .