Question

A body having $1680J$ of energy is supplied to $100g$ of water. If the entire amount of energy is converted into heat the rise in temperature of water (sp. heat of water = $4200JK{g}^{-1}{}^0{C}^{-1}$)

• A. ${0.4}^{\circ }C$
• B. ${40}^{\circ }C$
• C. $4^{\circ }C$
• D. ${44}^{\circ }C$

Answer 1

Answer: (C)

$4^{\circ }C$

If $\delta T$ is the rise in temperature, then the amount of heat supplied is $Q=mS\Delta T$ where $S=$ specific heat

Thus, $1680=\left(100/1000\right)\left(4200\right)\Delta T$ or $\Delta T=4^{o}C$