wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body having initial velocity of 10m/s moving on a rough surface comes to rest after moving 50m. What is coefficient of friction between the body and surface? (g=10m/s2)

A
0.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.1
Given :- Initial velocity of body (u) = 10 m/s
Final velocity of body (v) = 0 m/s
Distance covered (s) = 50 m
Acceleration due to gravity (g) = 10 m/s2

To Find :- coefficient of friction (μ)

Solution :- we know, By third equation of motion , i.e,
v2=u22as
100=2a×50
a=1m/s2

Now we know , coefficient of friction (μ) is given by ,
μ=ag
μ=1100.1
Hence , Option D(0.1) is correct.–––––––––––––––––––––––––


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon