Question

A body is dropped from rest at a height of 150m and similarly another body is dropped from the rest from a point 100m above the ground what is there difference in height after they have fallen in 2 sec and in 3 sec.

Answer 1

In two seconds .

for Ist object. u =0. t=2sec
the object is 150m abobe the ground
a =g= 10 (9.8)
s=ut+1/2at^2
s=0×2+1/2×10×2×2
s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 150-20=130M

for IInd object. u =0. t=2sec
a =g= 10 (9.8)
the object is 100m above the ground
a =g= 10 (9.8)
s=ut+1/2at^2
s=0×2+1/2×10×2×2
s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 100-20=80M



THE DISTANCE BETWEEN THE OBJECTS AFTER 2 SEC
===130-80=50


In three seconds

for Ist object. u =0. t=3sec
the object is 150m abobe the ground
a =g= 10 (9.8)
s=ut+1/2at^2
s=0×3+1/2×10×3^2
s=45

AFTER 3SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 150-45=105M

for IInd object. u =0. t=3sec
a =g= 10 (9.8)
the object is 100m abobe the ground
a =g= 10 (9.8)
s=ut+1/2at^2
s=0×3+1/2×10×3^2
s=45

AFTER 3SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 100-45=55M



THE DISTANCE BETWEEN THE OBJECTS AFTER 3 SEC
===105-55=50M