A body is executing S.H.M. When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocity of the body is 10 cm/sec and 8 cm/sec. Then the time period of the body is

2π sec

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π/2 sec

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π sec

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3π/2 sec

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Solution

The correct option is C
π sec

v = $ω \sqrt{a^{2} - y^{2}} \Rightarrow 10 = ω \sqrt{a^{2} - (4)^{2}} a n d 8 = ω \sqrt{a^{2} - (5)^{2}}$

On solving $ω = 2 \Rightarrow ω = \frac{2 π}{T} = 2 \Rightarrow= π s e c$

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A body is executing S.H.M. When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocity of the body is 10 cm/sec and 8 cm/sec. Then the time period of the body is

The correct option is C π sec v = ω√a2−y2⇒10=ω√a2−(4)2 and 8=ω√a2−(5)2 On solving ω=2⇒ω=2πT=2⇒=πsec

The correct option is C
π sec

v = $ω \sqrt{a^{2} - y^{2}} \Rightarrow 10 = ω \sqrt{a^{2} - (4)^{2}} a n d 8 = ω \sqrt{a^{2} - (5)^{2}}$

On solving $ω = 2 \Rightarrow ω = \frac{2 π}{T} = 2 \Rightarrow= π s e c$