A body is executing SHM. If the force acting on the body is 6N when the displacement is 2 cm, then the force acting on the body when the displacement is 3 cm in newton is:

6

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9

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4

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\sqrt{6}

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Solution

The correct option is B $9$ N
$F = m w^{2} x$
$\frac{F_{1}}{F_{2}} = \frac{x_{1}}{x_{2}}$
$F_{2} = \frac{3}{2} \times 6 N = 9 N$

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A body is executing SHM. If the force acting on the body is 6N when the displacement is 2 cm, then the force acting on the body when the displacement is 3 cm in newton is:

The correct option is B 9 NF=mw2xF1F2=x1x2F2=32×6 N=9 N

The correct option is B $9$ N
$F = m w^{2} x$
$\frac{F_{1}}{F_{2}} = \frac{x_{1}}{x_{2}}$
$F_{2} = \frac{3}{2} \times 6 N = 9 N$