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Question

A body is moving along a rough horizontal surface with an initial velocity 6 m/s. If the body comes to rest after travelling 9 m, then the coefficient of sliding firction will be

A
0.4
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B
0.2
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C
0.6
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D
0.8
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Solution

The correct option is B 0.2
We know that frictional force is given by F=μsN=μs×mg

where μs is the coefficient of sliding friction.

If a is the deceleration of the body,
ma=μs×mgμs=ag

Now, by third equation of motion we know that

v2u2=2as
v=0 (as body comes to rest)
a=u22s=622×9=2 m/s2
(ve sign shows that the body is retarding or slowing down)

μs=ag=210=0.2

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