A body is moving along a rough horizontal surface with an initial velocity 6m/s. If the body comes to rest after travelling 9m, then the coefficient of sliding firction will be
A
0.4
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B
0.2
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C
0.6
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D
0.8
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Solution
The correct option is B0.2 We know that frictional force is given by F=μsN=μs×mg
where μs is the coefficient of sliding friction.
If a is the deceleration of the body, ma=μs×mg⇒μs=ag
Now, by third equation of motion we know that
v2−u2=2as v=0 (as body comes to rest) ⇒a=−u22s=−622×9=−2m/s2
(−ve sign shows that the body is retarding or slowing down)