A body is moving along a rough horizontal surface with an initial velocity of 10ms−1. If the body comes to rest after travelling a distance of 12m, then the coefficient of sliding friction will be
A
0.5
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B
0.2
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C
0.4
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D
0.6
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Solution
The correct option is C0.4 Given, u=10ms−1, s=12m, v=0 By third equation of motion, v2=u2−2as 0=(10)2−2×a×12 24a=100 a=4.17ms−2 Coefficient of sliding friction is given by μ=ag=4.1710=0.41