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Question

A body is moving from rest under constant acceleration and let S1 be the displacement in the first (p−1) sec and S2 be the displacement in the first p sec. The displacement in (p2−p+1)nsec. will be

A
S1+S2
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B
S1S2
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C
S1S2
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D
S1/S2
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Solution

The correct option is B S1+S2
The initial velocity of body is zero, u=0
2rd equation of motion,
S=ut+12at2
S=12at2. . . . . .. .(1)
The displacement in time (P1) sec is
S1=12a(P1)2. . . . .(2)
The displacement at time P sec,
S2=12aP2. . . . . .(3)
Adding equation (2) and (3), we get
S1+S2=12a(2P22P+1). . . . . .(4)
The displacement at time (p2P+1)nsec
S=12a(2P22P+1). . . . .(5)
From equation (4) and (5),
S=S1+S2
The correct option is A.

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