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Question

A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels a distance S1 in the first 10 sec and a distance S2 in the next 10 sec, then

 



A

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B

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C

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D

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Solution

The correct option is B


As S= ut + 12at2

S1=12a(10)2=50a ..........(i)

The distance traveled in first 20s is 

S=12a(20)2=200a

We have

S2=SS1=150a

 S1=S23


Physics

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