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Question

# A particle, after starting from rest experiences constant acceleration for 20 seconds. If it covers a distance of S1 in first 10 seconds and distance S2 in next 10 seconds, then

A
S2=S1/2
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B
S2=S1
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C
S2=2S1
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D
S2=3S1
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Solution

## The correct option is D S2=3S1Let the constant acceleration be a Given, u=0 For first 10 seconds S1=ut+12at2 S1=0+12a(10)2 S1=50 a …….(1) Total displacement in 20 seconds S=0+12a(20)2=200a ⇒ S2=S–S1=150 a.....(2) From (1) and (2) S2S1=150a50a⇒ S2=3S1

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