    Question

# A body travels for 15 second starting from rest with constant acceleration . If it covers distances S1,S2 and S3 in the first five seconds, second five seconds and next five seconds respectively then the relation between S1,S2 and S3 is

A
S1=S2=S3
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B
5S1=3S2=S3
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C
S1=13S2=15S3
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D
S1=15S2=13S3
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Solution

## The correct option is C S1=13S2=15S3Let ‘v’ denotes speed and ‘a’ denotes acceleration.At t=0, v0= 0At t=5, v5= 5aAt t=10, v10= 10aFor interval-1, (t=0 to t=5)S1=v0*5 + (1/2)*a*52= 12.5aFor interval-2, (t=5 to t=10)S2= v5*5 + (1/2)*a*52= 37.5aFor interval-3, (t=10 to t=15)S3= v10*5 + (1/2)*a*52= 62.5aTherefore, S1: S2: S3= 1:3:5  Suggest Corrections  0      Similar questions  Related Videos   Acceleration
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