A body is moving from rest under constant acceleration and let S 1 be the displacement in the first p -1 sec and S 2 be the displacement in the first p sec- The displacement in p 2- p -1th sec- will be A- S1-S2B- S1 S2C- S1-S2D- S1 - S2

The correct option is A FromS=ut+1/2 a t^2 S_1=1/2a(P 1)^2 and S_2=1/2 a p^2 [AS u=0] FromS_n=u+a/2(2n 1) S_(p^2 P+1)^bk=a/2[2(P^2 P+1) 1]=a/2[2P^2 2P+1] ...

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Byju's Answer

Standard XII

Mathematics

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A body is mov...

Question

A body is moving from rest under constant acceleration and let S₁ be the displacement in the first $(p - 1)$ sec and S₂ be the displacement in the first p sec. The displacement in $(p^{2} - p + 1)^{t h}$ sec. will be

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Solution

The correct option is A
From $S = u t + \frac{1}{2} a t^{2}$

$S_{1} = \frac{1}{2} a (P - 1)^{2} a n d S_{2} = \frac{1}{2} a p^{2} [A S u = 0]$

From $S_{n} = u + \frac{a}{2} (2 n - 1)$

$S_{(p^{2} - P + 1)^{b k}} = \frac{a}{2} [2 (P^{2} - P + 1) - 1] = \frac{a}{2} [2 P^{2} - 2 P + 1]$

it is clear that $S_{(P^{2} - P + 1)^{b k}} = S_{1} + S_{2}$

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A body is moving from rest under constant acceleration and let S1 be the displacement in the first (p−1) sec and S2 be the displacement in the first p sec. The displacement in (p2−p+1)th sec. will be

The correct option is A From S=ut+12 a t2 S1=12a(P−1)2 and S2=12 a p2 [AS u=0] From Sn=u+a2(2n−1) S(p2−P+1)bk=a2[2(P2−P+1)−1]=a2[2P2−2P+1] it is clear that S(P2−P+1)bk=S1+S2

A body is moving from rest under constant acceleration and let S₁ be the displacement in the first $(p - 1)$ sec and S₂ be the displacement in the first p sec. The displacement in $(p^{2} - p + 1)^{t h}$ sec. will be