A body is projected along a rough horizontal surface with a velocity 6m/s. If the body comes to rest after travelling 9m, then coefficient of sliding friction, is (g=10m/s2)
A
0.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D0.2 Using newton's 2nd law Fnet=ma Retardation a=μmgm=μg=10μ Now, v2=u2+2as or 0=(6)2−2(10μ)(9) (since acceleration is negative) ∴μ=0.2