A body is projected along a rough horizontal surface with a velocity 6m/s. If the body comes to rest after travelling 9m, then coefficient of sliding friction, is (g=10m/s2)
A
0.5
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B
0.4
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C
0.6
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D
0.2
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Solution
The correct option is D0.2 Using newtons 2nd law Fnet=ma Retardation a=μmgm=μg=10μ Now, 0=u2−2as or 0=(62)−2(10μ)(9) ∴μ=0.2