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Question

A body is projected at an angle of 30 with the horizontal and with a speed of 30 ms1. What is the angle with the horizontal after 1.5 seconds ?
(g=10 ms2).

A
0
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B
30
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C
45
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D
60
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Solution

The correct option is A 0
Given, u=30 m/s . Let α be the angle of projectile with the horizontal after 1.5 seconds. Let v be the velocity of the projectile after 1.5 seconds.
vx=ux=ucosθvx=30cos30=153 m/s
Using first equation of motion for the vertical component of velocity, we get
vy=uygtvy=30sin3010×1.5=0
Vertical component of velocity becomes 0 when the body is at the highest point of the projectile. α=0

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