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Question

A body is projected from the top of a tower of height 32 m with a velocity of 20 m/s at an angle of 37∘ above the horizontal. Find the horizontal distance travelled before it hits the ground. (Take g=10 m/s2)

A
80 m
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B
48 m
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C
64 m
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D
32 m
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Solution

The correct option is C 64 mUsing second equation of motion, sy=uyt−1/2gt2 ⇒−32=20sin37∘t−5t2 ⇒−32=12t−5t2 ⇒5t2−20t+8t−32=0 ⇒(5t+8)(t−4)=0 ∴Time of flight t=4 s (taking positive value of time) Horizontal distance travelled depends only on the horizontal component of velocity and the horizontal component of velocity doesn’t change during the motion. Hence, horizontal distance travelled by the body before it hits the ground =ux×t =20cos37∘×4=20×45×4=64 m

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