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Question

# A body is projected from the top of a tower of height of 32 m with a velocity of 20 m/s at an angle of 37∘ below the horizontal. The time of flight of the projectile is (Take g=10 m/s2)

A
2 s
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B
0.8 s
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C
1.6 s
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D
4 s
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Solution

## The correct option is C 1.6 sTime of flight only depends on the vertical component of velocity. Initial vertical velocity uy=−20sin37∘=−20×35=−12 m/s (taking upward direction as positive) Displacement of the body when it reaches the ground h=−32 m Using second equation of motion, h=uyt−12gt2⇒−32=−12t−5t2=0⇒5t2+20t−8t−32=0⇒5t(t+4)−8(t+4)=0⇒t=85=1.6 s (taking positive value of time)

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