A body is projected vertically up with velocity $10 m / s$ . On reaching the ground, the magnitude of change in its velocity is

Zero

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20 m / s

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- 20 m / s

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None

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Solution

The correct option is B $20 m / s$
Initial velocity is $V_{i} = 10 m / s$
on reaching ground it will have same $k i n e t i c$ energy so the speed will be $10 m / s$ and the velocity will be
$V_{f} = - 10 m / s$ , $n e g a t i v e$ sign because $d i r e c t i o n$ get $i n v e r t e d .$
chage in velocity will be $V_{f} - V_{i} = - 10 - 10 = - 20 m / s$
$m a g n i t u d e$ of the change is $20 m / s$

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