A body is projected vertically upwards. The times corresponding to height h while ascending and while descending are $t_{1}$ and $t_{2}$ respectively. Then, the velocity of projection is:

$g \sqrt{t_{1} t_{2}}$

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$g \frac{t_{1} t_{2}}{t_{1} + t_{2}}$

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$\frac{g \sqrt{t_{1} t_{2}}}{2}$

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$\frac{g (t_{1} t_{2})}{2}$

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Solution

The correct option is D
$\frac{g (t_{1} t_{2})}{2}$

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A body is projected vertically upwards. The times corresponding to height h while ascending and while descending are t1 and t2 respectively. Then, the velocity of projection is:

The correct option is D g(t1t2)2

A body is projected vertically upwards. The times corresponding to height h while ascending and while descending are $t_{1}$ and $t_{2}$ respectively. Then, the velocity of projection is:

The correct option is D
$\frac{g (t_{1} t_{2})}{2}$