Question

A body is released from the top of a tower of height h. It takes t sec to reach the ground. Where will be the ball after time $\frac{t}{2}$ sec

• A. At h/2 from the ground
• B. At h/4 from the ground
• C. Depends upon mass and volume of the body
• D. At 3h/4 from the ground

Answer 1

The correct option is D At 3h/4 from the ground

Let the body after time $\frac{t}{2}$ be at x from the top, then
x=$\frac{1}{2}g\frac{t^2}{4}=\frac{g{t}^2}{8}...\left(i\right)$

h=$\frac{1}{2}g{t}^2...\left(ii\right)$
Eliminate t from (i) and (ii), we get x=$\frac{h}{4}$
$\therefore$ Height of the body from the ground =h-$\frac{h}{4}=\frac{3h}{4}$