Question

A body is released from the top of a tower of height H m. After 2 s, it is stopped and then instaneously released. What will be its height after next 2 s ?

• A. (H-5) m
• B. (H-10) m
• C. (H-20) m
• D. (H-40) m

Answer 1

The correct option is D

(H-40) m

For the first two seconds,

$h_1$ = $\frac{1}{2}$ $\times$ g $\times$ $2^2$ = 2g = 20 m

For the next 2 seconds,

$h_2$ = $\frac{1}{2}$ $\times$ g $\times$ $2^2$ = 20 m

Therefore height of the body = (H - 40)m