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Question

# A body is thrown upwards with velocity 100 m/s and it travels 5 m in the last second of its upward journey. If the same body is thrown upward with velocity 200 m/s, what distance will it travel in the last second of upward journey? (Given g=10 m/s2).

A
5m
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B
10m
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C
20m
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D
25m
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Solution

## The correct option is A 5mwe know the relationS=u+a2(2n−1)for case=1u=100ms−1,a=−10ms−2,s=5m5=100+(−102)(2n−1)we get n=10secondsfor case u=200 ms−1,a=−10 m s−1, V=0 ms−1 time =v−ua⇒0−200−10 time =20 seconds here n=20secondsS=u+aL(2n−1)S=20˙0−5(39)S=5 m so the answer is (A) 5m

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