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Question

A body is thrown upwards with velocity 40 m s−1 and it covers 5 m in the last second of its upward journey. If the same body is thrown upwards with velocity 80 m s−1, what distance will it travel in the last second of upward journey? (Take g = 10 m s−2)

A
5m
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B
10m
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C
15m
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D
20m
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Solution

The correct option is A 5mNow,v2=u2−2gs0=(80)2−(2)(10)(s)0=6400−20s20s=6400s=320metrev=u+gt0=80−10πt0=80−10t10t=80t=8secondsIn last secondS20=u+(12)g(2t−1)=80−(12)(10)(2×8−1)=80−5(15)=80−75=5metresA is the correct option.

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