A body is thrown vertically upwards and rises to a height of $10 m$ . The time taken by the body to reach the highest point is

1.4 s

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4.1 s

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1.24 s

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None of these

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Solution

The correct option is A $1.4 s$
when body reaches at top velocity it has zero.
$v^{2} = u^{2} - 2 g h$

$u = \sqrt{2 g h} = \sqrt{2 * 9.8 * 10} = 14 m / s$

The time $v = u - g t$

$t = \frac{u}{g} = \frac{14}{10} = 1.4 s$

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Q. If a body is thrown vertically upward and rises to a height of 10 m, then time taken by the body to reach the highest point is

Q. A body is thrown vertically upwards and rises to a height of 10 m. The time taken by the body to reach the highest point is (g = 9.8

m / s^{2}

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Q. A body is thrown vertically upwards and rises to a height of

10 m

. The velocity with which the body was thrown upwards is

(g = 9.8 m / s^{2})

An object is thrown vertically upwards and rises to a height of $10 c m$ . Calculate
(i) the velocity with which the object was thrown upwards and
(ii) the time taken by the object to reach the highest point.

A body is thrown vertically upwards and rises to a height of 10m. The velocity with which the body was thrown upwards is : (g = 9.8 $m / s^{2}$ )

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A body is thrown vertically upwards and rises to a height of 10m. The time taken by the body to reach the highest point is

The correct option is A 1.4swhen body reaches at top velocity it has zero.v2=u2−2ghu=√2gh=√2∗9.8∗10=14m/sThe time v=u−gtt=ug=1410=1.4s

A body is thrown vertically upwards and rises to a height of $10 m$ . The time taken by the body to reach the highest point is

The correct option is A $1.4 s$
when body reaches at top velocity it has zero.
$v^{2} = u^{2} - 2 g h$

$u = \sqrt{2 g h} = \sqrt{2 * 9.8 * 10} = 14 m / s$

The time $v = u - g t$

$t = \frac{u}{g} = \frac{14}{10} = 1.4 s$