A body is thrown vertically upwards and rises to a height of 10 m. The time taken by the body to reach the highest point is (g = 9.8 $m / s^{2}$ )

1.43 s

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4.1 s

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1.24 s

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Solution

The correct option is D 1.43 s
$S = u t + \frac{1}{2} a t^{2}$
$⟹ H = 0 - \frac{1}{2} g t^{2}$
$t = \sqrt{\frac{2 \times 10}{9.8}}$
$t = 1.43 s e c$

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A body is thrown vertically upwards and rises to a height of 10 m. The time taken by the body to reach the highest point is (g = 9.8 m/s2)

The correct option is D 1.43 sS=ut+12at2⟹H=0−12gt2t=√2×109.8t=1.43sec

A body is thrown vertically upwards and rises to a height of 10 m. The time taken by the body to reach the highest point is (g = 9.8 $m / s^{2}$ )

The correct option is D 1.43 s
$S = u t + \frac{1}{2} a t^{2}$
$⟹ H = 0 - \frac{1}{2} g t^{2}$
$t = \sqrt{\frac{2 \times 10}{9.8}}$
$t = 1.43 s e c$