Question

A body is thrown vertically upwards with a velocity of $19.6{ms}^{-1}$. The position of the body after $4s$ will be

• A. At the highest point
• B. At the mid-point of the line joining the starting point and the highest point
• C. At the starting point
• D. None of the above

Answer 1

Answer: (C)

At the starting point

Clearly the time taken by the particle to reach the highest point is given by $v=ugt$

or, $t=\frac{u-v}{g}=\frac{19.6-0}{9.8}$

or, $t=2s$

Therefore, the particle will reach at the starting point itself after $4s$.