A body is thrown with a velocity of 20ms−1 from a building of height 15m. If the angle of projection is 30∘ above the horizontal, the time of flight and the range of the projectile are respectively.
(Take g=10m/s2)
A
1s,30m
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B
3s,30m
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C
3s,30√3m
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D
1s,30√3m
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Solution
The correct option is C3s,30√3m Displacement of the body in the vertical direction when the body reaches the ground =−15m
(Take downward direction as –ve)
Using second equation of motion, we get −H=usinθ×t−12gt2 ⇒−15=20×12×t−5t2 ⇒5t2−10t−15=0 ⇒t2−2t−3=0 ⇒t=3s (Neglecting negative value)
Range of the projectile =ucosθ×t =20×√32×3 =30√3m