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Standard XII

Physics

Introduction

A body is thr...

Question

A body is thrown with some velocity from the ground. Maximum height when it is thrown at $60$ to horizontal is $90$ m. What is the height reached when it is thrown at $30$ to the horizontal:

90

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45

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30

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15

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Solution

The correct option is C $30$ m
maximum height $H = \frac{v_{o}^{2} s i n^{2} θ}{2 g}$
$90 = \frac{v_{o}^{2} s i n^{2} 60^{o}}{20}$

$v_{o}^{2} = 2400$
height reached at angle 30
$H = \frac{v_{o}^{2} s i n^{2} 30^{o}}{20}$

$⟹ H = \frac{2400 \times {0.5}^{2}}{20} = 30 m$

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A body is thrown with some velocity from the ground. Maximum height when it is thrown at 60 to horizontal is 90 m. What is the height reached when it is thrown at 30 to the horizontal:

The correct option is C 30 mmaximum height H=v2osin2θ2g90=v2osin260o20v2o=2400height reached at angle 30H=v2osin230o20⟹H=2400×0.5220=30m

A body is thrown with some velocity from the ground. Maximum height when it is thrown at $60$ to horizontal is $90$ m. What is the height reached when it is thrown at $30$ to the horizontal:

The correct option is C $30$ m
maximum height $H = \frac{v_{o}^{2} s i n^{2} θ}{2 g}$
$90 = \frac{v_{o}^{2} s i n^{2} 60^{o}}{20}$

$v_{o}^{2} = 2400$
height reached at angle 30
$H = \frac{v_{o}^{2} s i n^{2} 30^{o}}{20}$

$⟹ H = \frac{2400 \times {0.5}^{2}}{20} = 30 m$