1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A body when projected at an angle 60o with the horizontal covers a horizontal distance of 90m in 5 s. Instead, if the body is thrown upward with the same velocity. The maximum height attained by it is _____ m. (Takeg=10ms−2)

A
68.8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
64.8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
34.8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
36.4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B 64.8Let the velocity of projectile be u.Angle of projection with the horizontal θ=60oSo, initial velocity in horizontal direction ux=ucosθ=u×cos60o=0.5uHorizontal distance covered in 5 seconds is 90 mThus 0.5u=905⟹ u=36 m/sNow the body is projected vertically upwards with a speed u=36 m/sMaximum height reached H=u22g=36×362×10=64.8 m

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Problem Solving Using Pseudo-Forces
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program